c96b8350-6608-11eb-a37e-e580c0970d9b作业答案10（105-111）（周洋鑫）考研资料.pdf

2022 全程班高分必刷 800 题答案解析新浪微博考研数学周洋鑫12022 年全程班高分必刷 800 题作业答案第二章 一元函数微分学【105】解析：232yxaxb62yxa111yab 120yba 解得3,3ab【106】解析：2224334122 14144111xxxxxxxxyxxx326444 143 14 11248111xxxxxxyxxx令102yx 得102xy 时，102xy 时，故拐点为1 2,2 9【107】解析：ln 11 ln 11limlimlim11xxxxxexxeyaxxxx x1 ln 1111 ln 111limlimlim212121xxxxxxxxxeeexxeeexxx1111lim12222xxxeelimlimln 1limln111xxxxxxxxby axexeexxxlimln 1limln 111xxxxxxxexexxlimlim ln 11 011xxxxex 故斜渐近线为1yx2022 全程班高分必刷 800 题答案解析新浪微博考研数学周洋鑫2limlimln 1limlim ln 11 0111xxxxxxxxyeexx 故在 X 轴左侧有水平渐近线，无斜渐近线【108】解析：22111 0limlim111 01xxxxeeyee故有水平渐近线1y 220012limlim01xxxxeye 故有垂直渐近线0 x 选 D【109】解析：222222arctan 1arctan 1limlimlimlim1 0111xxxxxxyxxaxxxxx 322232221+arctan 1+1+limlimarctan 1+lim11xxxxxxxxxbyaxxxxx 222222222 arctan 1+1+11+arctan 1+11+limlim12xxxxxxxxxxxx222211limarctan 1limlim0022211xxxxxxx故斜渐近线为2yx【110】解析：arctanarctanarctanarctan222222211111111xxxxx xxyexeeexxx则 arctan124122yxyee 极大值 20yxye 极小值arctan211limlim1xxxyxaeeexx arctanarctanarctan2221limlim1limlimxxxxxxxbye xxee xx eeearctanarctan22lim1limxxxxe x eearctan2limarctanlim2xxxe xxe2022 全程班高分必刷 800 题答案解析新浪微博考研数学周洋鑫322100111111limarctanlim21xttttteeeett 令201lim21teeet 故 X 轴右侧斜渐近线为2ye xearctan22221limlim11xxxyxaeexx arctanarctanarctan2222limlim1lim1xxxxxxbyxxexx eearctanarctanarctan222lim1limlimarctanlim2xxxxxxxx eexxe22122200011111arctan12limlim1lim1211xtttttttett 令故在 X 轴左侧的斜渐近线为2yx【111】解析：3322222|21,1 1021112yxyyx 则点的坐标为1,0