060.刻意练习解析(高等数学)【公众号：小盆学长】免费分享.pdfVIP免费

2025最新版《考研数学大纲基础精讲一本通》新浪微博@考研数学周洋鑫公众号:周洋鑫12025年周洋鑫《考研数学大纲基础精讲一本通》刻意练习解析目录第一章函数、极限与连续...................................................................................2基础讲义第11、13页.................................................................................2基础讲义第23页.........................................................................................3基础讲义第36-37页...................................................................................4基础讲义第44页.........................................................................................7第二章一元函数微分学.......................................................................................9基础讲义第52、54页.................................................................................9基础讲义第62页.......................................................................................10基础讲义第64页.......................................................................................10基础讲义第71页.......................................................................................10第三章不定积分.................................................................................................11基础讲义第84页.......................................................................................112025最新版《考研数学大纲基础精讲一本通》新浪微博@考研数学周洋鑫公众号:周洋鑫2第一章函数、极限与连续基础讲义第11、13页【刻意练习1】【答案】C.【解析】()2limlimcos01xxxfxxx→+→+==+.()2221111limlim1coslim22xxxgxxxxx→+→+→+=−==.因此()()limlimxxgxfx→+→+，即x→+时，()()fxgx，故选C.【刻意练习2】【答案】A.【解析】()()130001414123limlimlim2sin23xxxxxfxxx→→→+−===.()()()223355000tantantantanlimlimlimxxxxxxxxxxxgxxx→→→−++−==22201tantanlim3xxxxxx→++=−222220001tantanlimlimlim3xxxxxxxxxx→→→=−++()111113=−++=−.因此()()00limlimxxfxgx→→，即0...