微信公众号《考研路上的幸福哥》,考研干货最多的公众平台2014年考研数学一答案解析1、C1sin1sinlimlim11limlimsin01sinxxxxyxxxyxkxxyxxyxyxx存在斜渐近线2、D解:令()()()()(0)(1)(1)Fxfxgxfxfxfx有(0)(1)0FF,()()(0)(1)Fxfxff,()()Fxfx当()0fx时,()Fx在[0,1]上是凹的,所以()0Fx,从而()()fxgx3、D区域如图:选择极坐标:xy-1-10微信公众号《考研路上的幸福哥》,考研干货最多的公众平台2112cossin000201111000cos,sincos,sin,,xxdfrrrdrdfrrrdrdxfxydydxfxydy若为直角坐标4、A解析:222222222220322I(cossin)(cossin2cos2sin2sincos)2(cossin2sin)2(2)322a0,2Ixaxbxdxxaxbxaxxbxxabxxdxxaxbxbxxdxabbb当时,最小故a,cosx+b,sinx=2sinx5、B解析:2141332320a000000000(1)0(1)00000(1)(1)()()babcdcdababacdcbdcdababadcbcdcdababadbccdcdabbcadcdadbc6、A解析:微信公众号《考研路上的幸福哥》,考研干货最多的公众平台1231132231122123121213231323123123+k)()0++k)00+k++k+100=0=1=0000llklll已知,,无关设(即(从而,无关反之,若,无关,不一定有,,无关例如,,,7、B(AB)(A)P(B)[P(AB)P(AB)]P(B)(0.3P(AB))0.5P(AB)0.3(BA)P(B)P(AB)0.50.30.2PPP8、(D)解:2121()2YXX,2121211[()]()22EYEXXEXEX,2121211[()]()24DYDXXDXDX。1121()[()()]2Yfyfyfy,1121221[()()]()22yEYfyfydyEXEXEY,2222112121[()()]()22yEYfyfydyEXEX,2222211112122222121212221212122212121221212211()()()24122()()241241()()241()4DYEYEYEXEXEXEXEXEXEXEXEXEXDXDXEXEXEXEXDXDXEXEXEXEXDXDXEXEXDY微信公众号《考研路上的幸福哥》,考研干货最多的公众平台9、22'2'2'''(1,0,1)(x,y,z)=x(1siny)y(1sinx)zF...