1广东省2010年普通高校本科插班生招生考试《高等数学》试题答案及评分参考一、单项选择题(本大题共5小题,每小题3分,共15分)1.B2.A3.C4.D5.D二、填空题(本大题共5小题,每小题3分,共15分)6.07.0xy8.29.2712xxyCeCe10.3三、计算题(本大题共8小题,每小题6分,共48分)11.解:原式2cotlim4(2)xxx22csc1lim88xx.12.解:2Δ0Δ02Δsinsin2Δ(Δ)(0)Δ(0)limlimΔΔxxxxfxfxfxxΔ0Δ02sin2Δsin2Δlim(Δsin)0limΔΔΔxxxxxxxxΔ0sin2Δ2lim22Δxxx.13.解:有题意知1aeb①又因为11123422,2xxxaaayebxyeebxxx所以,有题意知22320aeaebaeb②由①和②解得2,3abe.14.解一:原式222cos(1cos)coscotsinsinxxxdxdxxdxxx2221sin(csc1)sindxxdxx1cotsinxxCx.解二:原式221sin22sin2xdxx221csccsc()2222xxxdxdxddxcot2xxC.15.解:令1xet,则222ln(1),1txtdxdtt所以3ln1033322ln5222212211xtdtedxdtdttt22(arctan3arctan2).16.解:11(sin)dxdxxxyexedxClnln(sin)xxexedxC1(coscos)xxxdxCxsincosxCxxx.17.解:设223(,,)1Fxyzxxyz,则122,2,ln3zzxyzFzxyFxyFxxz所以212222,ln3ln3zyxzzzFFzyzxzxyxFxxzyFxxz.18.解:画出积分区域D解方程组212yxyx,可求得切点为(1,2)32110222xxDxydxdydxxydy2112122200|(12)xxxydxxxxdx112222300111(1)(1)266xdxx四、综合题(本大题共2小题,第19小题10分,第20小题12分,共22分)19.解:0Φ()(1)xxttdt在(,)上可导,Φ()(1)xxx令Φ()(1)0xxx,得驻点120,1xx列表如下:x(,0)0(0,1)1(1,)Φ()x+0-0+Φ()x单调增极大值单调减极小值单调增极大值Φ(0)0极小值101Φ(1)(1)6xxdx.20.解:①2ln(1)2()(1)xxxfxex2ln(1)2212ln(1)()21xxexxxx2222(1)ln(1)2xxx.②111(2)(2)(2)2fxdxfxdx令2tx,则121(2)()2fxdxftdt421221lim122ttttt22121lim12222ttet.