课时作业44空间向量及其运算[基础达标]一、选择题1.已知a=(2,3,-4),b=(-4,-3,-2),b=x-2a,则x=()A.(0,3,-6)B.(0,6,-20)C.(0,6,-6)D.(6,6,-6)解析:由b=x-2a,得x=4a+2b=(8,12,-16)+(-8,-6,-4)=(0,6,-20).答案:B2.对于空间一点O和不共线的三点A,B,C,有6OP=OA+2OB+3OC,则()A.O,A,B,C四点共面B.P,A,B,C四点共面C.O,P,B,C四点共面D.O,P,A,B,C五点共面解析:由6OP=OA+2OB+3OC,得OP-OA=2(OB-OP)+3(OC-OP),即AP=2PB+3PC,故AP,PB,PC共面,又它们有公共点P,因此,P,A,B,C四点共面,故选B.答案:B3.已知空间四边形OABC中,OA=a,OB=b,OC=c,点M在OA上,且OM=2MA,N为BC中点,则MN=()A.a-b+cB.-a+b+cC.a+b-cD.a+b...