TM_D_7638_
_10_rus
D 763810 STANDARD TEST METHOD FOR DETERMINATION OF FATTY ACIDS AND ESTERS IN GLYCERIN ():2568-15/ASTM :24.02.2015 2015 (ASTM International)100 rr Harbor Drive,West Conshohocken,PA 19428,USA.ASTM International ,ASTM International.-,ASTM International ,.This translation is executed by FBU“CIC“Interstandard”of Federal Agency on Technical Regulating and Metrology under the license of American Society for Testing and Materials(ASTM International)100 rr Harbor Drive,West Conshohocken,PA 19428,USA.ASTM International does not approve and does not confirm these translations and in any cases only the English version published with a sign of ASTM International copyright can be considered as the original version.Reproduction of the specified translations by any Party,except for ASTM International or FBU“CIC“Interstandard”,is strictly forbidden according to the USA legislation and international copyright.-,.9,-49,-1,119991.:(499)236-54-49:(499)230-13-72 E-mail:interstgost.ru http:/www.interstandart.ru/ASTM D 7638-10 D 7638-10 1 D 7638;,.()1.1.1 .1.2,.1.3 ,.,.8.1 ASTM D15 ,D15.93 .01 2010.2010.DOI:10.1520/D7638-10.1ASTM D 7638-10 2.2.1 ASTM:2 D 1193 D 4725,2.2 :31 3 3.3.1:3.1.1 -1,2,3-,C3H5(OH)3(),1,2,3-,1,2,3-,(CAS#56-81-5)3.1.2 FA&E 3.1.3 ,.D 4725.4.4.1 (FA&E).4.2 (FA&E ).,2 ASTM,ASTM www.astm.org ASTM serviceastm.org.ASTM.Document Summary ASTM.3 U.S.Pharmacopeia(USP),12601 Twinbrook Pkwy.,MD 20852-1790,http:/www.usp.org.2ASTM D 7638-10,.1 .5.5.1 .5.2 ,200-250,24/40().5.3,5,0,02 ,NIST.5.5.4,5 0,01.5.5 ,(.5.1),550.6.6.1 .,.,.3ASTM D 7638-10 6.2 ,II D 1193.2 ,500 5,.7,0 0,1;(0,1 N NaOH)(0,1 N HCl),.7.7.1 1 100 (95%),.(.2).7.2 (0,5 N HCl)1000 40 43 ,.0,001 N(.1 2).7.3 (0,5 N)22,0 NaOH 1,.(0,001 N).(CO2)(.1 2).3 0,5 0,05 N.7.4 ,(.6.2).4ASTM D 7638-10 8.8.1 .8.2 ,(MSDS),.8.3 .9.9.1 50 0,1 200 250.9.2 50 .9.3 5,00 0,1 0,5 N .4 ,;.9.4 3 5 .(PTFE)4.5 (0,4)FA&E .4 Teflon Dupont.5ASTM D 7638-10 9.5 .5 .9.6 ,.9.7 1 .9.8 0,5 N .(S),.9.9 ,(-.9.7),.25 0,1 .9.1 9.8.50.9.10 .9.2 9.8,50 .,(B).10.10.1 (50 0,5 N NaOH):(B C)N 0,5=FA&E 0,5 N NaOH 50 (1):6ASTM D 7638-10 -0,5 N,(0,01),S-,(0,01),N-HCl,0,001.:=4,95 HCl,S=4,65 HCl,N=HCl=0,525 N.(4,95 4,65)0,525 FA&E=0,5=0,32 0,5 N NaOH 50 (2)11.11.1 0,01 NaOH,50 .12.5 12.1 .1.12.2 ,.13.13.1;5 -ASTM International RR:D15-1026.7ASTM D 7638-10 ;.1 (%)-x xS Sr SR r R A 0,30 0,07 0,004 0,068 0,012 0,189 0,54 0,05 0,009 0,047 0,025 0,131 8ASTM D 7638-10 9ASTM International -,.,.,.-ASTM International.,.,.ASTM International,100 Barr Harbor Drive,PO Box C700,West Conshohocken,PA 19428-2959,United States.610-832-9585,610-832-9555 E-mail:serviceastm.org ASTM:(www.astm.org).ASTM(www.astm.org/COPYRIGHT/).